https://www.youtube.com/watch?v=mXLD...r3GhPXDX6Vhbpg
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this is my favorite one:
how about a little sweet talk before you blow your links all over the place
it's like taking a course on physics without actually having to take a course on physics; cut straight to the meat
and it was made for cal tech, it's not some dumbed down explanation given to on the science channel by morgan freeman
and cal tech is pretty much the MIT of the west coast; quality stuff
No.
hi plug drugs , not gonna watch those video's just popped into tell you that
sneaking in college lectures that most people have to pay for by watching videos of them uploaded to youtube is kinda like the matricks,
Neo: "I know kung fu"
Plug Drugs: "I know calculus"
i know derivatives now; i can tell you the slope of the tangent line at any point on a curve following the traditional y=x^2+mx+b format
plug drugs not gonanread those posts, sosryr if thought i was
god damnit i came here today and made this thread to impress all of you WHAT IS IT GOING TO TAKE
write a song about lisa and rootbeer then make a youtube video of it and post the youtube video i will watch that video of you shredding on your guitar if you have not sold it for drugs
i dont want to fucking watch math lessons in my spare time
lol
this sounds like it would make an awesome threadQuote:
Originally Posted by Autistic Spectrum
plug drugs you are sitting on a goldmine, you know you can shred
Go squirt drugs up your ass
h is the distance on the x axis between two points on a curve (a curve in the y=x^2+mx+b format) which form a secant line
we can find the slope of a tangent line of any point on the curve by finding the derivative:
f'(a)=[f(a+h)-f(a)]/h, as h approaches 0
so for y=x^2-8x+9, the derivative will be
= ([(a+h)^2-8(a+h)+9]-[a^2-8a+9])/h
= (a^2+2ah+h^2-8a-8h+9-a^2+8a-9)/h
= (2ah+h^2-8h)/h =(2a+h-8)
= 2a-8
the derivative of the curve y=x^2-8x+9 is 2x-8
This will tell you the slope of the tangent line for any point on that curve by plugging the x value of that point into the derivative. So, for the point (3,-6) on the curve y=x^2-8x+9, you just plug the x value (3) into the derivative (which is 2x-8), which gives you -2.
So the slope of the tangent line at (3,-6) is -2.
You now know derivatives, that's half of calculus.
i;ll slope my dick on your grandma's tangent
find the derivative of raw dogging your grams
The force behind the prefixed curve =
ERRRGGHQuote:
Originally Posted by Autistic Spectrum
It equals smoke more joints
tomorrow we'll touch on integrals
Ok great.
And dp can touch on your grandma.
noobs
thats might feel revilutionary but you arent doing anything new
theres blogs that get youthrough this shit
Feels revolutionary