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05-20-2014
this is my favorite one:
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05-20-2014
how about a little sweet talk before you blow your links all over the place
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05-20-2014
it's like taking a course on physics without actually having to take a course on physics; cut straight to the meat
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05-20-2014
and it was made for cal tech, it's not some dumbed down explanation given to on the science channel by morgan freeman
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05-20-2014
and cal tech is pretty much the MIT of the west coast; quality stuff
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05-20-2014
hi plug drugs , not gonna watch those video's just popped into tell you that
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05-20-2014
sneaking in college lectures that most people have to pay for by watching videos of them uploaded to youtube is kinda like the matricks,
Neo: "I know kung fu"
Plug Drugs: "I know calculus"
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05-20-2014
i know derivatives now; i can tell you the slope of the tangent line at any point on a curve following the traditional y=x^2+mx+b format
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05-20-2014
plug drugs not gonanread those posts, sosryr if thought i was
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05-20-2014
god damnit i came here today and made this thread to impress all of you WHAT IS IT GOING TO TAKE
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05-20-2014
write a song about lisa and rootbeer then make a youtube video of it and post the youtube video i will watch that video of you shredding on your guitar if you have not sold it for drugs
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05-20-2014
i dont want to fucking watch math lessons in my spare time
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05-20-2014
plug drugs you are sitting on a goldmine, you know you can shred
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05-20-2014
h is the distance on the x axis between two points on a curve (a curve in the y=x^2+mx+b format) which form a secant line
we can find the slope of a tangent line of any point on the curve by finding the derivative:
f'(a)=[f(a+h)-f(a)]/h, as h approaches 0
so for y=x^2-8x+9, the derivative will be
= ([(a+h)^2-8(a+h)+9]-[a^2-8a+9])/h
= (a^2+2ah+h^2-8a-8h+9-a^2+8a-9)/h
= (2ah+h^2-8h)/h =(2a+h-8)
= 2a-8
the derivative of the curve y=x^2-8x+9 is 2x-8
This will tell you the slope of the tangent line for any point on that curve by plugging the x value of that point into the derivative. So, for the point (3,-6) on the curve y=x^2-8x+9, you just plug the x value (3) into the derivative (which is 2x-8), which gives you -2.
So the slope of the tangent line at (3,-6) is -2.
You now know derivatives, that's half of calculus.
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05-20-2014
i;ll slope my dick on your grandma's tangent
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05-20-2014
find the derivative of raw dogging your grams
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05-20-2014
tomorrow we'll touch on integrals
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05-20-2014
noobs
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05-20-2014
thats might feel revilutionary but you arent doing anything new
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05-20-2014
theres blogs that get youthrough this shit
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